HOW LONG WILL AN "H" CYLINDER LAST IF IT HAS 1350 PSIG IN IT AND IT RUNS AT 6 LPM?
Accepted Solution
A:
Answer:11.78 hours.Step-by-step explanation:We are asked to find the time that an "H" cylinder will last having 1350 PSI of gas in it at a flow of 6 LPM.[tex]\text{Duration of tank (in minutes)}=\frac{\text{Tank pressure (in PSI)}\times\text{Conversion factor}}{\text{Flow (LPM)}}[/tex][tex]\text{Duration of H tank (in minutes)}=\frac{1350\times 3.14}{6}[/tex][tex]\text{Duration of H tank (in minutes)}=\frac{4239}{6}[/tex][tex]\text{Duration of H tank (in minutes)}=706.5[/tex]To convert the time in hours, we will divide 706.5 by 60 as i hour equals 60 minutes.[tex]\text{Duration of H tank (in hours)}=\frac{706.5}{60}[/tex][tex]\text{Duration of H tank (in hours)}=11.775[/tex]Therefore, it will take 11.78 hours to last the given cylinder.