Q:

Two of the steps in the derivation of the quadratic formula are shown below. Step 6: = b^2-4ac/4a^2= ( x+b/2a )^2 Step 7: = +✔️b^2-4ac/2a= x + b/2aWhich operation is performed in the derivation of the quadratic formula moving from Step 6 to Step 7? subtracting b/2a from both sides of the equation squaring both sides of the equation taking the square root of both sides of the equation taking the square root of the discriminant

Accepted Solution

A:
Answer: C) Taking the square root of both .
Step-by-step explanation: We are given the two of the steps in the derivation of the quadratic formula:Step 6: =>  [tex]\frac{b^2-4ac}{4a^2} = (x+\frac{b}{2a})^2[/tex]Step 7: =>  [tex]\sqrt\frac{b^2-4ac}{4a^2}}= x+\frac{b}{2a})[/tex]We can see in step, we have square on right side on ( x+b/2a ).So, we need to get rid square by taking square root on both sides.Square root of ( x+b/2a )^2 is just x+b/2a.And we got  [tex]\sqrt\frac{b^2-4ac}{4a^2}} [/tex] on left side.Also if we simplify denominator [tex]\sqrt{4a^2}[/tex], we get 2a.So, final expression for step 7 is Step 7: =>  [tex]\frac{\sqrt{b^2-4ac}}{2a}}=x+\frac{b}{2a}[/tex].Therefore, they performed operation:  C) Taking the square root of both .