Use the quadratic formula to solve the equation. 2x^2-6x+1=0 Enter your answers, in simplified radical form, in the boxes. x=__or x=please send me image and explain work

Answer:(3 (pm) sqrt(7))/2Step-by-step explanation:First step: Identify a,b, and ca=2b=-6c=1Second step: Find b^2-4ac (this is called the discriminant-I will call this D)(-6)^2-4(2)(1)=36-8=28Third step: Find the square root of the discriminant aka sqrt(D)sqrt(28)Let's see if we can simplify sqrt(28)Here is there a factor of 28 that is a perfect square? How about 4? Yep!sqrt(28)=sqrt(4)sqrt(7)=2sqrt(7).Fourth Step: What is -b? If b=-6 then -b=6.Fifth step: What is 2a?  2(2)=4So the formula isx=(-b (pm) sqrt(D))/(2a)orx=(step4 (pm) step 3)/(step 5)x=(6 (pm) 2sqrt(7))/4Simplifyx=(3 (pm) sqrt(7))/2*pm means plus or minus*sqrt( ) means square root of the number that follows in the ( )